JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry
In ammonium-phosphomolybdate, the oxidation state of Mo is \({ }^{+}\) \(..........\).
- A \(8\)
- B \(4\)
- C \(10\)
- D \(6\)
Answer & Solution
Correct Answer
(D) \(6\)
Step-by-step Solution
Detailed explanation
\(\left( NH _4\right)_3 PO _4 \cdot 12 MoO _3\) Let \(X =\) oxidation state of \(Mo\) in \(MoO _3\) \(X +(-2) \times 3=0\) \(X =+6\)
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