JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)

If the solubility product of \(PbS\) is \(8 \times 10^{-28}\), then the solubility of \(PbS\) in pure water at \(298\; K\) is \(x \times 10^{-16}\; mol\; L ^{-1}\). The value of \(x\) is \(\dots\). [Given \(\sqrt2 = 1.41\)]

A \(281\)
B \(282\)
C \(283\)
D \(284\)

Verified Solution

Answer & Solution

Correct Answer

(B) \(282\)

Step-by-step Solution

Detailed explanation

\(K _{ sp }= S ^{2}\) \(S =\sqrt{ K _{ sp }}=\sqrt{8 \times 10^{-28}}=2 \sqrt{2} \times 10^{-14}\) \(=2.82 \times 10^{-14}\) \(=282 \times 10^{-16}\) Ans. \(=282\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Match List\(-I\) with List\(-II\):

List\(-I\) (Parameter)	List\(-II\) (Unit)
\((a)\) Cell constant	\((i)\) \(\mathrm{S}\, \mathrm{cm}^{2} \,\mathrm{~mol}^{-1}\)
\((b)\) Molar conductivity	\((ii)\) Dimensionless
\((c)\) Conductivity	\((iii)\) \(\mathrm{m}^{-1}\)
\((d)\) Degree of dissociation of electrolyte	\((iv)\) \(\Omega^{-1} \,\mathrm{~m}^{-1}\)

Choose the most appropriate answer from the options given below :

JEE Mains 2021 Easy

Explore more questions on app

From JEE Mains

Explore more questions on app

List \(I\) (compounds)	List \(II\) (Value of \(Pk_a\))
\(A\). ethanol	\(I\). \(10.0\)
\(B\). phenol	\(II\). \(15.9\)
\(C\). \(m\)-nitrophenol	\(III\). \(7.1\)
\(D\). \(p\)-nitrophenol	\(IV\). \(8.3\)