JEE Mains · Chemistry · STD 12 - 9. Amines
From \(6.55 \mathrm{~g}\) of aniline, the maximum amount of acetanilide that can be prepared will be _______ \(\times 10^{-1} \mathrm{~g}\).
- A \(90\)
- B \(96\)
- C \(97\)
- D \(95\)
Answer & Solution
Correct Answer
(D) \(95\)
Step-by-step Solution
Detailed explanation
\(93 \mathrm{~g}\) aniline form \(135 \mathrm{gm}\) acetanlide so \(6.55 \mathrm{~g}\) anilne form \(\frac{135}{93} \times 6.55=9.5\) \(95 \times 10^1\)
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