JEE Mains · Chemistry · STD 11 - 8.3. Organic chemistry purification and characterization
A student has been given 0.314 g of an organic compound and asked to estimate Sulphur. During the experiment, the student has obtained 0.4813 g of barium sulphate. The percentage of sulphur present in the compound is __________
(Given Molar mass in \(g mol^{-1}\) S: 32, \(BaSO_{4}\): 233)
- A 42.10%
- B 63.15%
- C 21.05%
- D 48.24%
Answer & Solution
Correct Answer
(C) 21.05%
Step-by-step Solution
Detailed explanation
\(\% S=\frac{32}{233} \times \frac{0.4813}{0.314} \times 100\) \(=21.052 \%\)
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