JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
\(1\, L\) aqueous solution of \(H _{2} SO _{4}\) contains \(0.02\, m\) mol \(H _{2} SO _{4} .50\, \%\) of this solution is diluted with deionized water to give \(1\, L\) solution \((A).\) In solution \((A)\), \(0.01\, m \,mol\) of \(H _{2} SO _{4}\) are added. Total \(m\) \(mols\) of \(H _{2} SO _{4}\) in the final solution is \(......\times 10^{3}\, m\, mols.\)
- A \(3\)
- B \(1\)
- C \(2\)
- D \(0\)
Answer & Solution
Correct Answer
(D) \(0\)
Step-by-step Solution
Detailed explanation
\(n _{ H _{2} SO _{4}}\) in \(Sol ^{ n } A =50 \%\) of original solution \(=0.01\, m \,mol\). \(n _{ H _{2} SO _{4}}\) in Final solution \(=0.01+0.01\) \(=0.02 \,m\,mol\) \(=0.00002 \times 10^{3} \,m\,mol\)
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