JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
\(0.01\) moles of a weak acid \(HA \left( K _{ a }=2.0 \times 10^{-6}\right)\) is dissolved in \(1.0\, L\) of \(0.1\, M\, HCl\) solution. The degree of dissociation of \(HA\) is ............. \(\times 10^{-5}\) (Round off to the Nearest Integer). [Neglect volume change on adding \(HA\). Assume degree of dissociation \(<< 1]\)
- A \(6\)
- B \(3\)
- C \(2\)
- D \(7\)
Answer & Solution
Correct Answer
(C) \(2\)
Step-by-step Solution
Detailed explanation
\(\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\quad\quad\quad HA \rightleftharpoons \quad H ^{+}+\quad A ^{-}\) Initial conc. \(\quad0.01 M\quad \, 0.1 M \quad\quad 0\) Equ. conc. \(\,(0.01- x )\quad(0.1+ x )\quad xM\) Now,…
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