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JEE Advanced · Physics · 24. Ray Optics

The graph between object distance \(u\) and image distance \(v\) for a lens is given below. The focal length of the lens is

  1. A \(5 \pm 0.1\)
  2. B \(5 \pm 0.05\)
  3. C \(0.5 \pm 0.1\)
  4. D \(0.5 \pm 0.05\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(5 \pm 0.05\)

Step-by-step Solution

Detailed explanation

From the lens formula:
\(\frac{1}{f}=\frac{1}{v}-\frac{1}{u}\) we have, \(\frac{1}{f}=\frac{1}{10}-\frac{1}{-10}\) or \(f=+5\)
Further, \(\Delta u=0.1\) and \(\Delta v=0.1\)
(from the graph)
Now, differentiating the lens formula we have,
\(
\frac{\Delta f}{f^2}=\frac{\Delta v}{v^2}+\frac{\Delta u}{u^2} \text { or } \Delta f=\left(\frac{\Delta v}{v^2}+\frac{\Delta u}{u^2}\right) f^2
\)
Substituting the values we have,
\(
\Delta f=\left(\frac{0.1}{10^2}+\frac{0.1}{10^2}\right)(5)^2 \Rightarrow f \pm \Delta f\) \(=5 \pm 0.05
\)
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