JEE Advanced · Physics · 12. Thermal Properties
Parallel rays of light of intensity are incident on a spherical black body kept in surroundings of temperature 300 K. Take Stefan-Boltzmann constant and assume that the energy exchange with the surroundings is only through radiation. The final steady state temperature of the black body is close to
- A 330 K
- B 660 K
- C 990 K
- D 1550 K
Answer & Solution
Correct Answer
(A) 330 K
Step-by-step Solution
Detailed explanation
Rate of radiation energy lost by the sphere = Rate of radiation energy incident on it
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