JEE Advanced · Chemistry · 22. d & f Block
A solution of colourless salt \(\mathrm{H}\) on boiling with excess \(\mathrm{NaOH}\) produces a non-flammable gas. The gas evolution ceases after sometime. Upon addition of \(\mathrm{Zn}\) dust to the same solution, the gas evolution restarts. The colourless salt (s) \(\mathrm{H}\) is (are)
- A \(\mathrm{NH}_4 \mathrm{NO}_3\)
- B \(\mathrm{NH}_4 \mathrm{NO}_2\)
- C \(\mathrm{NH}_4 \mathrm{Cl}\)
- D \(\left(\mathrm{NH}_4\right)_2 \mathrm{SO}_4\)
Answer & Solution
Correct Answer
(B) \(\mathrm{NH}_4 \mathrm{NO}_2\)
Step-by-step Solution
Detailed explanation
\(
\begin{aligned}
& \mathrm{NH}_4 \mathrm{NO}_3+\mathrm{NaOH} \longrightarrow \mathrm{NaNO}_3+\mathrm{NH}_3+\mathrm{H}_2 \mathrm{O} \\
& \mathrm{NaNO}_3+8[\mathrm{H}] \mathrm{NaOH}+\mathrm{NH}_3+2 \mathrm{H}_2 \mathrm{O} \\
& \mathrm{NH}_4 \mathrm{NO}_2+\mathrm{NaOH} \longrightarrow \mathrm{NaHO}_2+\mathrm{NH}_3+\mathrm{H}_2 \mathrm{O} \\
& \mathrm{NaNO}_2+6[\mathrm{H}] \longrightarrow \mathrm{NaOH}+\mathrm{NH}_3+\mathrm{H}_2 \mathrm{O}
\end{aligned}
\)
\begin{aligned}
& \mathrm{NH}_4 \mathrm{NO}_3+\mathrm{NaOH} \longrightarrow \mathrm{NaNO}_3+\mathrm{NH}_3+\mathrm{H}_2 \mathrm{O} \\
& \mathrm{NaNO}_3+8[\mathrm{H}] \mathrm{NaOH}+\mathrm{NH}_3+2 \mathrm{H}_2 \mathrm{O} \\
& \mathrm{NH}_4 \mathrm{NO}_2+\mathrm{NaOH} \longrightarrow \mathrm{NaHO}_2+\mathrm{NH}_3+\mathrm{H}_2 \mathrm{O} \\
& \mathrm{NaNO}_2+6[\mathrm{H}] \longrightarrow \mathrm{NaOH}+\mathrm{NH}_3+\mathrm{H}_2 \mathrm{O}
\end{aligned}
\)
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