JEE Advanced · Physics · 13. Thermodynamics
One mole of an ideal monatomic gas undergoes an adiabatic expansion in which its volume becomes eight times its initial value. If the initial temperature of the gas is and the universal gas constant , then how much is the decrease in its internal energy (in ) ?
- A 1000
- B 1500
- C 900
- D 500
Answer & Solution
Correct Answer
(C) 900
Step-by-step Solution
Detailed explanation
\(V_i=V\)
\(V_f=8 V\)
For adiabatic process \(\{\gamma=5 / 3\) for monoatomic gas \(\}\)
\(\begin{array}{l}T_1 \cdot V_1^{\gamma-1}=T_2 \cdot V_2^{\gamma-1} \\100(V)^{\frac{2}{3}}=T_2(8 V)^{\frac{2}{3}} \\T_2=25 K\end{array}\)
Loss in internal energy
\(\Delta U=n C_v \Delta T=1\left(\frac{f R}{2}\right)[100-25]=12\) \(\times~ 75=900 J\)
\(V_f=8 V\)
For adiabatic process \(\{\gamma=5 / 3\) for monoatomic gas \(\}\)
\(\begin{array}{l}T_1 \cdot V_1^{\gamma-1}=T_2 \cdot V_2^{\gamma-1} \\100(V)^{\frac{2}{3}}=T_2(8 V)^{\frac{2}{3}} \\T_2=25 K\end{array}\)
Loss in internal energy
\(\Delta U=n C_v \Delta T=1\left(\frac{f R}{2}\right)[100-25]=12\) \(\times~ 75=900 J\)
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