JEE Advanced · Physics · 17. Electrostatics
Four charges and of same magnitude are fixed along the x axis at and , respectively. A positive charge q is placed on the positive y axis at a distance . Four options of the signs of these charges are given in List I. The direction of the forces on the charge q is given in List II. Match List I with List II and select the correct answer using the code given below the lists.

| List I | List II | ||
| A. | all positive | ||
| B. | positive; negative | Q. | |
| C. | positive; negative | ||
| D. | positive; negative |
- A a-r;b-p;c-q;d-s;
- B a-q;b-s;c-r;d-p;
- C a-s;b-q;c-r;d-p;
- D a-r;b-p;c-s;d-q;
Answer & Solution
Correct Answer
(D) a-r;b-p;c-s;d-q;
Step-by-step Solution
Detailed explanation
P: By and and F is in +y
Q: By and and F is in +ve x.
R: By and , F is in +ve y
By and , F is in -ve y
But later has more magnitude, since its closer to (0, b). Therefore net force is in - y
S: By and , F is in +ve x and by and , F is in -x, but later is more in magnitude, since its closer to (0, b). Therefore net force is in -ve x.

Q: By and and F is in +ve x.
R: By and , F is in +ve y
By and , F is in -ve y
But later has more magnitude, since its closer to (0, b). Therefore net force is in - y
S: By and , F is in +ve x and by and , F is in -x, but later is more in magnitude, since its closer to (0, b). Therefore net force is in -ve x.

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