JEE Advanced · Physics · 13. Thermodynamics
An ideal gas is undergoing a cyclic thermodynamic process in different ways as shown in the corresponding P-V diagrams in column 3 of the table. Consider only the path from state 1 to state 2. W denotes the corresponding work done on the system. The equations and plots in the table have standard notations as used in thermodynamic process. Here is the ratio of heat capacities at constant pressure and constant volume. The number of moles in the gas in n.
| Column – 1 | Column – 2 | Column – 3 |
| (I) \(W_{1 \rightarrow 2}=\) \(\frac{1}{\gamma-1}\left(P_2 V_2-P_1 V_1\right)\) | (i) Isothermal | (P) ![]() |
| (II) \(W_{1 \rightarrow 2}=\) \(-P V_2+P V_1\) | (ii) Isochoric | (Q)![]() |
| (III) \(W_{1 \rightarrow 2}=0\) | (iii) Isobaric | (R) ![]() |
| (IV) \(W_{1 \rightarrow 2}=\)\(-n R T \ln \left(\frac{V_2}{V_1}\right)\) | (iv) Adiabatic | (S) ![]() |
- A
- B
- C
- D
Answer & Solution
Correct Answer
(D)
Step-by-step Solution
Detailed explanation
It is for an adiabatic process. The correct match is (II) (iii) (P).
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