JEE Advanced · Physics · 24. Ray Optics

An extended object is placed at point $O$ , $10 cm$ in front of a convex lens $L_{1}$ and a concave lens $L_{2}$ is placed $10 cm$ behind it, as shown in the figure. The radii of curvature of all the curved surfaces in both the lenses are $20 cm$ . The refractive index of both the lenses is $1.5$ . The total magnification of this lens system is:

A $0.4$
B $0.8$
C $1.3$
D $1.6$

Verified Solution

Answer & Solution

Correct Answer

(B) $0.8$

Step-by-step Solution

Detailed explanation

For convex lens,

\frac{1}{f} = (\frac{μ_{2}}{μ_{1}} - 1) (\frac{1}{R_{1}} - \frac{1}{R_{2}}) \Rightarrow \frac{1}{f_{1}} = (\frac{3}{2} - 1) (\frac{1}{20} - \frac{1}{- 20})

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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A)	$\vec{r} (t) = α t \hat{i} + β \hat{j}$	P)	$\vec{p}$
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