JEE Advanced · Physics · 8. Rotational Motion
A solid sphere is in pure rolling motion on an inclined surface having inclination \(\theta\).

- A frictional force acting on sphere is \(f=\mu m g \cos \theta\)
- B \(f\) is disspative force
- C friction will increase its angular velocity and decreases its linear velocity
- D If \(\theta\) decreases, friction will decrease
Answer & Solution
Correct Answer
(D) If \(\theta\) decreases, friction will decrease
Step-by-step Solution
Detailed explanation
In case of pure rolling,
\(
\begin{aligned}
& f=\frac{m g \sin \theta}{1+\frac{m R^2}{I}} \\
\therefore & f \propto \sin \theta
\end{aligned}
\)
(upwards)
Therefore, as \(\theta\) decreases force of friction will also decrease.
\(
\begin{aligned}
& f=\frac{m g \sin \theta}{1+\frac{m R^2}{I}} \\
\therefore & f \propto \sin \theta
\end{aligned}
\)
(upwards)
Therefore, as \(\theta\) decreases force of friction will also decrease.
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