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JEE Advanced · Mathematics · 4. P&C

Consider 4 boxes, where each box contains 3 red balls and 2 blue balls. Assume that all 20 balls are distinct. In how many different ways can 10 balls be chosen from these 4 boxes so that from each box at least one red ball and one blue ball are chosen?

  1. A 21816
  2. B 85536
  3. C 12096
  4. D 156816
Verified Solution

Answer & Solution

Correct Answer

(A) 21816

Step-by-step Solution

Detailed explanation

Let the four boxes be Box-1, Box-2, Box-3 and Box-4. Each of the box has 3 red balls and 2 blue balls.

10 balls can be chosen in:
Case I - When exactly one box gives four balls
Case II - When exactly two boxes gives three balls
Required number of ways= Number of ways in Case I + Number of ways in Case II.
\(={ }^4 C_1\left[{ }^2 C_1+{ }^3 C_1\right]\left({ }^3 C_1{ }^2 C_1\right)^3+{ }^4 C_2[{ }^3 C_2{ }^2 C_1\) \(+{ }^3 C_1{ }^2 C_2]^2\left[{ }^3 C_1{ }^2 C_1\right]^2\)
=4563+63×2+3262
=4320+17496=21816
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