JEE Advanced · Mathematics · 4. P&C
Consider boxes, where each box contains red balls and blue balls. Assume that all balls are distinct. In how many different ways can balls be chosen from these boxes so that from each box at least one red ball and one blue ball are chosen?
- A
- B
- C
- D
Answer & Solution
Correct Answer
(A)
Step-by-step Solution
Detailed explanation
Let the four boxes be Box-1, Box-2, Box-3 and Box-4. Each of the box has red balls and blue balls.

balls can be chosen in:
Case I - When exactly one box gives four balls
Case II - When exactly two boxes gives three balls
Required number of ways Number of ways in Case I Number of ways in Case II.
\(={ }^4 C_1\left[{ }^2 C_1+{ }^3 C_1\right]\left({ }^3 C_1{ }^2 C_1\right)^3+{ }^4 C_2[{ }^3 C_2{ }^2 C_1\) \(+{ }^3 C_1{ }^2 C_2]^2\left[{ }^3 C_1{ }^2 C_1\right]^2\)

balls can be chosen in:
Case I - When exactly one box gives four balls
Case II - When exactly two boxes gives three balls
Required number of ways Number of ways in Case I Number of ways in Case II.
\(={ }^4 C_1\left[{ }^2 C_1+{ }^3 C_1\right]\left({ }^3 C_1{ }^2 C_1\right)^3+{ }^4 C_2[{ }^3 C_2{ }^2 C_1\) \(+{ }^3 C_1{ }^2 C_2]^2\left[{ }^3 C_1{ }^2 C_1\right]^2\)
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