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JEE Advanced · Physics · 13. Thermodynamics

A mixture of ideal gas containing 5 moles of monatomic gas and 1 mole of rigid diatomic gas is initially at pressure P0, volume V0 and temperature T0. If the gas mixture is adiabatically compressed to a volume V04, then the correct statement(s) is/are,
(Given 21.2= 2.3; 23.2=9.2; R is gas constant)

  1. A The final pressure of the gas mixture after compression is in between 9P0 and 10P0.
  2. B The average kinetic energy of the gas mixture after compression is in between 18RT0 and 19RT0.
  3. C The work W done during the process is 13RT0.
  4. D Adiabatic constant of the gas mixture is 1.6.
Verified Solution

Answer & Solution

Correct Answer

(A) The final pressure of the gas mixture after compression is in between 9P0 and 10P0.

Step-by-step Solution

Detailed explanation

Here, n1=5,CP1=52R,CV1=32Rn2=1, CP2=72R,CV2=52Rγmix=n1CP1+n2CP2n1CV1+n2CV2=85=1.6
Work done, W=P1V1-P2V2γ-1, In adiabatic process
Now, for adiabatic compression
P1V1r=P2V2r
P0V08/5=P2V048/5
P2=9.2P0A is correct.
Now, W=P0V0-9.2P0V043/5=-13RT0C is correct
W=13 RT0
Again T1V1γ-1=T2V2γ-1
T2=T126/5=2.3T0
Average kinetic energy of gas mixture =nCVmixT2
=23RT0 B is incorrect
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