JEE Advanced · Physics · 23. EM Waves
A fission reaction is given by , where and are two particles. Considering to be at rest, the kinetic energies of the products are denoted by and , respectively. Let the binding energies per nucleon of and be 7.5 MeV, 8.5 MeV, and 8.5 MeV respectively. Considering different conservation laws, the correct option(s) is (are)
- A \(x=n, y=n, K_{S r}=129 MeV , K_{X e}\)\(=86 MeV\)
- B \(x=p, y=e^{-}, K_{S r}=129 MeV , K_{X e}\)\(=86 MeV\)
- C \(x=p, y=n, K_{S r}=129 MeV , K_{X e}\)\(=86 MeV\)
- D \(x=n, y=n, K_{S r}=86 MeV , K_{X e}\)\(=129 MeV\)
Answer & Solution
Correct Answer
(A) \(x=n, y=n, K_{S r}=129 MeV , K_{X e}\)\(=86 MeV\)
Step-by-step Solution
Detailed explanation
...(i)
\(-Q=E_B=236 \times 7.5-140 \times 8.5\)\(-94 \times 8.5\)
...(ii)
Since, both & have same KE
both particles should have same mass & lighter body will have higher KE.
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Physics
- A heavy nucleus of half-life minutes undergoes alpha-decay with probability of and beta-decay with probability of . Initially, the number of nuclei is . The number of alpha-decays of in the first one hour is:JEE Advanced 2021 Easy
- Three identical capacitors have a capacitance of each and they are uncharged initially. They are connected in a circuit as shown in the figure and is then filled completely with a dielectric material of relative permittivity . The cell electromotive force (emf) . First the switch is closed while the switch is kept open. When the capacitor is fully charged, is opened and is closed simultaneously. When all the capacitors reach equilibrium, the charge on is found to be . The value of =____________.
JEE Advanced 2018 Medium - Consider a Vernier callipers in which each 1 cm on the main scale is divided into 8 equal divisions and a screw gauge with 100 divisions on its circular scale. In the Vernier callipers, 5 divisions of the Vernier scale coincide with 4 divisions on the main scale and in the screw gauge, one complete rotation of the circular scale moves it by two divisions on the linear scale. Then:JEE Advanced 2015 Medium
- A bi-convex lens is formed with two thin plano-convex lenses as shown in the figure. Refractive index \(n\) of the first lens is \(1.5\) and that of the second lens is \(1.2\). Both the curved surface are of the same radius of curvature \(R=14\) \(\mathrm{cm}\). For this bi-convex lens, for an object distance of 40 \(\mathrm{cm}\), the image distance will be
JEE Advanced 2012 Medium - Paragraph:
Light guidance in an optical fiber can be understood by considering a structure comprising of thin solid glass cylinder of refractive index \(n_{1}\) surrounded by a medium of lower refractive index \(n_{2}\). The light guidance in the structure takes place due to successive total internal reflections at the interface of the media \(n_{1}\) and \(n_{2}\) as shown in the figure. All rays with the angle of incidence \(i\) less than a particular value \(i_{m}\) are confined in the medium of refractive index \(n_{1}\). The numerical aperture (NA) of the structure is defined as \(\sin i_{m}\).
Question:
If two structures of same cross-sectional area, but different numerical apertures \(N A_{1}\) and \(N A_{2}\left(N A_{2} < N A_{1}\right)\) are joined longitudinally, the numerical aperture of the combined structure isJEE Advanced 2015 Medium - In plotting stress versus strain curves for two materials \(P\) and \(Q\), a student by mistake puts strain on the \(y\)-axis and stress on the \(x\)-axis as shown in the figure. Then the correct statement(s) is(are)
JEE Advanced 2015 Medium
More PYQs from JEE Advanced
- Statement 1 For practical purposes, the earth is used as a reference at zero potential in electrical circuits.
and Statement 2 The electrical potential of a sphere of radius \(R\) with charge \(Q\) uniformly distributed on the surface is given by \(\frac{Q}{4 \pi \varepsilon_0 R}\).JEE Advanced 2008 Easy - For a radioactive material, its activity and rate of change of its activity are defined as and , where is the number of nuclei at time . Two radioactive sources (mean life ) and (mean life ) have the same activity at . Their rates of change of activities at are and , respectively. If , then the value of isJEE Advanced 2015 Medium
- A cubical solid aluminum (bulk modulus \(=-\text V \frac{\text{dP}}{\text{dV}}=70\text{ GPa}\)) block has an edge length of 1 m on the surface of the earth. It is kept on the floor of a 5 km deep ocean. Taking the average density of water and the acceleration due to gravity to be \(10^3\text{ kg m} ^{-3}\) and \(10\text{ ms} ^{-2}\), respectively, the change in the edge length of the block in mm is _____________ .JEE Advanced 2020 Easy
- A solid sphere of radius R and density ρ is attached to one end of a mass-less spring of force constant k. The other end of the spring is connected to another solid sphere of radius R and density 3 ρ The complete arrangement is placed in a liquid of density 2ρ and is allowed to reach equilibrium. The correct statement(s) is (are)JEE Advanced 2013 Medium
- Paragraph:
The reaction of \(\mathrm{K}_{3}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\) with freshly prepared \(\mathrm{FeSO}_{4}\) solution produces a dark blue precipitate called Turnbull's blue. Reaction of \(\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\) with the \(\mathrm{FeSO}_{4}\) solution in complete absence of air produces a white precipitate \(\mathbf{X}\), which turns blue in air. Mixing the \(\mathrm{FeSO}_{4}\) solution with \(\mathrm{NaNO}_{3}\), followed by a slow addition of concentrated \(\mathrm{H}_{2} \mathrm{SO}_{4}\) through the side of the test tube produces a brown ring.
Question:
Among the following, the brown ring is due to the formation ofJEE Advanced 2021 Easy - The value of is equal toJEE Advanced 2016 Hard