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JEE Advanced · Physics · 18. Capacitance

A circuit is connected as shown in the figure with the switch \(S\) open. When the switch is closed, the total amount of charge that flows from \(Y\) to \(X\) is

  1. A zero
  2. B \(54 \mu \mathrm{C}\)
  3. C \(27 \mu \mathrm{C}\)
  4. D \(81 \mu \mathrm{C}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(27 \mu \mathrm{C}\)

Step-by-step Solution

Detailed explanation

From \(Y\) to \(X\) charge flows to plates \(a\) and \(b\).
\(
\left(q_0+q_b\right)_i=0,\left(q_0+q_b\right)_f=27 \mu \mathrm{C}
\)


\(\therefore 27 \mu \mathrm{C}\) charge flows from \(Y\) to \(X\).
\(\therefore\) Correct option is (c)
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