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JEE Advanced · Physics · 20. Magnetism & Current

A charged particle is introduced at the origin x=0, y=0, z=0 with a given initial velocity v . A uniform electric field E  and a uniform magnetic field B exist everywhere. The velocity v , electric field E  and a uniform magnetic field B are given in the columns below
Column 1 Column 2 Column 3
1. Electron with  v=2E0B0x^  (i) E=E0z^ (P)  B=-B0x^
2. Electron with  v=2E0B0y^ (ii)  E=-E0y^ (Q)  B=B0x^
3.Proton with v =0 (iii)  E=-E0x^ (R)  B=-B0y^
4. Proton with  v=2E0B0x^ (iv)  E=E0x^ (S)  B=-B0z^
In which case would the particle move in a straight line along the negative direction of y axis

  1. A (4)  (ii)  (S)
  2. B (3)  (ii)  (P)
  3. C (2)  (iii)  (Q)
  4. D (3)  (ii)  (R)
Verified Solution

Answer & Solution

Correct Answer

(D) (3)  (ii)  (R)

Step-by-step Solution

Detailed explanation

For particle to move in -ve y-direction, either its velocity must be in –ve y-direction (if initial velocity ≠ 0) and force should be parallel to velocity or it must experience a net force in –ve y-direction only (if initial velocity = 0)
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