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JEE Advanced · Mathematics · 22. Functions

Paragraph:
If a continuous \(f\) defined on the real line \(R\), assume positive and negative values in \(R\), then the equation \(f(x)=0\) has a root in \(R\). For example, if it is known that a continuous function \(f\) on \(R\) is positive at some point and its minimum values is negative, then the equation \(f(x)=0\) has a root in \(R\).
Consider \(f(x)=k e^x-x\) for all real \(x\), where \(k\) is real constant.Question:
The line \(y=x\) meets \(y=k e^x\) for \(k \leq 0\) at

  1. A
    no point
  2. B
    one point
  3. C
    two points
  4. D
    more than two points
Verified Solution

Answer & Solution

Correct Answer

(B)
one point

Step-by-step Solution

Detailed explanation

\[
\text { Let } y=x \text { intersect the curve } y=k e^x \text { at exactly one point when } k \leq 0 \text {. }
\]

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