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JEE Advanced · Mathematics · 11. Sets & Relations

Let S=1,2,3,.9. For k=1,2,5, let Nk be the number of subsets of S, each containing five elements out of which exactly k are odd. Then N1+N2+N3+N4+N5=

  1. A 125
  2. B 252
  3. C 210
  4. D 126
Verified Solution

Answer & Solution

Correct Answer

(D) 126

Step-by-step Solution

Detailed explanation

N1+N2+N3+N4+N5= Total ways – {when no odd} Total ways =9C5
From JEE Advanced
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