JEE Advanced · Mathematics · 6. Binomial Theorem
Let \(X=\left({ }^{10} C_1\right)^2+2\left({ }^{10} C_2\right)^2+3\left({ }^{10} C_3\right)^2+\ldots+\) \(10\left({ }^{10} C_{10}\right)^2\), where \({ }^{10} C_r, r \in\{1,2, \ldots, 10\}\) denote binomial coefficients. Then, the value of \(\frac{1}{1430} X\) is _____________.
- A 646
- B 514
- C 562
- D 612
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(A) 646
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