JEE Advanced · Mathematics · 32. Probability
Paragraph:
Box \(1\) contains three cards bearing numbers \(1,2,3\); box \(2\) contains five cards bearing numbers \(1,2,3,4,5\); and box \(3\) contains seven cards bearing numbers \(1,2,3,4,5,6,7\). A card is drawn from each of the boxes. Let \(x_{i}\) be the number on the card drawn from the \(i^{t h}\) box, \(i=1,2,3\).
Question:
The probability that \(x_{1}+x_{2}+x_{3}\) is odd, is
- A
- B
- C
- D
Answer & Solution
Correct Answer
(B)
Step-by-step Solution
Detailed explanation
Case I: One odd, 2 even
Total number of ways
Case II: All 3 odd
Number of ways
Favourable ways = 53
Required probability
Total number of ways
Case II: All 3 odd
Number of ways
Favourable ways = 53
Required probability
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