JEE Advanced · Mathematics · 5. Sequences & Series

Let \(a_1, a_2, a_3, \ldots ., a_{100}\) be an arithmetic progression with \(a_1=3\) and \(S_p=\sum_{i=1}^p a_i\), \(1 \leq p \leq 100\). For any integer \(n\) with \(1 \leq n \leq 20\), let \(m=5 n\). If \(\frac{S_m}{S_n}\) does not depend on \(n\), then \(a_2\) is

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Answer & Solution

Correct Answer

(C) 3

Step-by-step Solution

Detailed explanation

Given, \(a_1=3, m=5 n\) and \(a_1, a_2, \ldots\) are in AP. \(\therefore \frac{S_m}{S_n}=\frac{S_{5 n}}{S_n}\) is independent of \(n\). Now, \( \frac{\frac{5 n}{2}[2 \times 3+(5 n-1) d]}{\frac{n}{2}[2 \times 3+(n-1) d]}\) \(\Rightarrow \frac{f\{(6-d)+5 n\}}{(6-d)+n}\) independent of \(n\), if \(\begin{aligned} 6-d= & 0 \Rightarrow d=6 \\ \therefore a_2= & a_1+d=3+6=9 \\ & \text { Or }\end{aligned}\)
If \(d=0\) \(\frac{S_m}{S_n}\) is independent of \(n\).
\(\therefore a_2=3\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

	List- $I$		List- II
$(I)$	$2 h + k$	$(P)$	$6$
$(I I)$	$\frac{L e n g t h o f Z W}{L e n g t h o f X Y}$	$(Q)$	$\sqrt{6}$
$(I I I)$	$\frac{A r e a o f t r i a n g l e M Z N}{A r e a o f t r i a n g l e Z M W}$	$(R)$	$\frac{5}{4}$
$(I V)$	$α$	$(S)$	$\frac{21}{5}$
		$(T)$	$2 \sqrt{6}$
		$(U)$	$\frac{10}{3}$

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