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JEE Advanced · Mathematics · 16. Limits

If β=limx0ex3-1-x313+1-x212-1sinxxsin2x, then the value of 6β is

  1. A 5
  2. B 10
  3. C 13
  4. D 17
Verified Solution

Answer & Solution

Correct Answer

(A) 5

Step-by-step Solution

Detailed explanation

β=limx0ex3-1-x313+1-x212-1sinxx·sin2xx2·x2 β=limx01+x3+x62!+-1-13x3+-19x6++-12x2-18x4+x-x33!+x3
From JEE Advanced
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