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JEE Advanced · Mathematics · 28. Area Under Curves

Area of the region {x,yR2: yx+3, 5yx+915} is equal to

  1. A 16
  2. B 43
  3. C 32
  4. D 53
Verified Solution

Answer & Solution

Correct Answer

(C) 32

Step-by-step Solution

Detailed explanation

If x+3<0y (x+3) & y0
If x+30y (x+3) & y0
Also
5yx+915
x5y+90 & x6
Intersection point of line & parabolas
5y=x+9 & y 2 =| x+3 | (y0)
( x+9 5 ) 2 =| x+3 |
x 2 +18x+81=25x+75 or 25x75
x 2 7x+6=0 or x 2 +43x+156=0
x=1,6 or x=39,4
So Clearly, x=1,y=2
and when x=4,y=1 are required points
Drawing all these, we get this graph.

Shaded portion is required area.
Clearly required area = area (trapezium ABCD) - A1+A2 .......(i)
area (trapezium ABCD) =121+25=152
A1= -4-3-x+3dx
=23
and A1= -31x+312dx=163
From equation (i), we get required area =152-23+163=32
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