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JEE Advanced · Mathematics · 29. Differential Eqns

A curve passes through the point  1 , π 6 . Let the slope of the curve at each point x , y be y x + sec y x , x  >  0 . Then the equation of the curve is

  1. A sin y x = log x + 1 2
  2. B cosec  y x = log x + 2
  3. C sec  2y x = log x + 2
  4. D cos  2y x = log x + 1 2
Verified Solution

Answer & Solution

Correct Answer

(A) sin y x = log x + 1 2

Step-by-step Solution

Detailed explanation

Given slope at (x, y) is dydx=yx+secyx......i
let yx=ty=xt 
From JEE Advanced
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