JEE Advanced · Chemistry · 21. p Block (G15-18)
The pair(s) of reagents that yield paramagnetic species is/are
- A Na and excess of
- B K and excess of
- C Cu and dilute
- D and 2- ethylanthraquinol
Answer & Solution
Correct Answer
(A) Na and excess of
Step-by-step Solution
Detailed explanation
A) sodium (Na) when dissolved in excess liquid ammonia, forms a blue coloured paramagnetic solution.
B) \(\text K +\text O _2 \longrightarrow \underset{\text { (potassium superoxide) }}{\text{KO} _2}\) and \(\text{KO} _2\) is paramagnetic.
C) \(3\text{Cu} +\underset{\text { (dilute) }}{8 \text{HNO} _3} \longrightarrow 3 \text{Cu} \left(\text{NO} _3\right)_2+2 \text{NO}\) \(+~4\text H _2\text O\)
Where "NO" is paramagnetic.
D)

B) \(\text K +\text O _2 \longrightarrow \underset{\text { (potassium superoxide) }}{\text{KO} _2}\) and \(\text{KO} _2\) is paramagnetic.
C) \(3\text{Cu} +\underset{\text { (dilute) }}{8 \text{HNO} _3} \longrightarrow 3 \text{Cu} \left(\text{NO} _3\right)_2+2 \text{NO}\) \(+~4\text H _2\text O\)
Where "NO" is paramagnetic.
D)

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