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JEE Advanced · Chemistry · 24. Haloalkanes & Haloarenes

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The amount of energy required to break a bond is same as the amount of energy released when the same bond is formed. In gaseous state, the energy required for homolytic cleavage of a bond is called Bond Dissociation Energy (BDE) or Bond Strength. BDE is affected by \(s\)-character of the bond and the stability of the radicals formed. Shorter bonds are typically stronger bonds. BDEs for some bonds are given below:





Question:
\(\mathrm{CH}_{4}(\mathrm{~g})+\mathrm{Cl}_{2}(\mathrm{~g}) \stackrel{\text { light }}{\longrightarrow} \mathrm{CH}_{3} \mathrm{Cl}(\mathrm{g})+\mathrm{HCl}(\mathrm{g})\) the correct statement is

  1. A Initiation step is exothermic with ΔH°=-58 kcal mol-1.
  2. B Propagation step involving CH3 formation is exothermic with ΔH°=-2 k cal mol-1
  3. C Propagation step involving CH3Cl formation is endothermic with ΔH°=+27 k cal mol-1
  4. D The reaction is exothermic with ΔH°=-25 k cal mol-1.
Verified Solution

Answer & Solution

Correct Answer

(D) The reaction is exothermic with ΔH°=-25 k cal mol-1.

Step-by-step Solution

Detailed explanation

CH4g+Cl2glightCH3Clg+HClg ΔHr=BDEreactansBDEproducts =ECH+EClClECClEHCl
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