JEE Advanced · Chemistry · 22. d & f Block
\(\mathrm{CuSO}_4\) decolourises on addition of \(\mathrm{KCN}\), the product is
- A \(\left[\mathrm{Cu}(\mathrm{CN})_4\right]^{2-}\)
- B \(\mathrm{Cu}^{2+}\) get reduced to form \(\left[\mathrm{Cu}(\mathrm{CN})_4\right]^{3-}\)
- C \(\mathrm{Cu}(\mathrm{CN})_2\)
- D \(\mathrm{CuCN}\)
Answer & Solution
Correct Answer
(D) \(\mathrm{CuCN}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{CuSO}_4\) decolourise on addition of \(\mathrm{KCN}\), the product is \(\mathrm{CuCN}\) along with \((\mathrm{CN})_2\) but in excess of KCN is form colourless potassium tetra cyano cuperate (I)
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