JEE Advanced · Chemistry · 9. Redox Reactions
At room temperature, disproportionation of an aqueous solution of in situ generated nitrous acid \(\left(\mathrm{HNO}_2\right)\) gives the species
- A \(\mathrm{H}_3 \mathrm{O}^{+}, \mathrm{NO}_3^{-}\)and \(\mathrm{NO}\)
- B \(\mathrm{H}_3 \mathrm{O}^{+}, \mathrm{NO}_3{ }^{-}\)and \(\mathrm{NO}_2\)
- C \(\mathrm{H}_3 \mathrm{O}^{+}, \mathrm{NO}^{-}\)and \(\mathrm{NO}_2\)
- D \(\mathrm{H}_3 \mathrm{O}^{+}, \mathrm{NO}_3{ }^{-}\)and \(\mathrm{N}_2 \mathrm{O}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{H}_3 \mathrm{O}^{+}, \mathrm{NO}_3^{-}\)and \(\mathrm{NO}\)
Step-by-step Solution
Detailed explanation
\(3 \mathrm{HNO}_2(\mathrm{aq}) \rightleftharpoons \mathrm{H}_3 \mathrm{O}^{+}+\mathrm{NO}_3^{-}+2 \mathrm{NO}\)
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