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JEE Advanced · Chemistry · 4. Chemical Bonding

Assuming 2s  2p mixing is NOT operative, the paramagnetic species among the following is

  1. A Be2
  2. B B2
  3. C C2
  4. D N2
Verified Solution

Answer & Solution

Correct Answer

(C) C2

Step-by-step Solution

Detailed explanation

Assuming that no 2s-2p mixing takes place
(i) \(Be _2 \rightarrow \sigma 1 s^2, \sigma^* 1 s^2, \sigma 2 s^2, \sigma^* 2 s^2\) (diamagnetic)
(ii) \(B _2 \rightarrow \sigma 1 s^2, \sigma^* 1 s^2, \sigma 2 s^2, \sigma^* 2 s^2, \sigma 2 p _{ z }^2,{ }_{\pi 2 p _{ y }^0}^{\pi 2 p _{ x }^0}\) (diamagnetic)
(iii) \(C _2 \rightarrow \sigma 1 s^2, \sigma^* 1 s^2, \sigma 2 s^2, \sigma^* 2 s^2, \sigma 2 p _{ z }^2\),\(\begin{array}{cc}\pi 2 p _{ x }^1, & \pi^* 2 p _{ x }^0 \\ \pi 2 p _{ y }^1, & \pi^* 2 p _{ y }^0,\end{array}\) \(\sigma^* 2 p _{ z }^0\) (paramagnetic)
(iv) \(N _2 \rightarrow \sigma 1 s^2, \sigma^* 1 s^2, \sigma 2 s^2, \sigma^* 2 s^2, \sigma 2 p _{ z }^2\), \(\begin{array}{cc}\pi 2 p _{ x }^2 & \pi^* 2 p _{ x }^0 \\ \pi 2 p _{ y }^2, & \pi^* 2 p _{ y }^0,\end{array}\) \(\sigma^* 2 p _{ z }^0\) (diamagnetic)
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