JEE Advanced · Chemistry · 21. p Block (G15-18)
Aqueous solution of \(\text{Na} _2\text S_2\text O _3\) on reaction with \(\text{Cl} _2\) gives
- A \(\mathrm{Na}_2 \mathrm{~S}_4 \mathrm{O}_6\)
- B \(\mathrm{NaHSO}_4\)
- C \(\mathrm{NaCl}\)
- D \(\mathrm{NaOH}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{NaHSO}_4\)
Step-by-step Solution
Detailed explanation
Sodium thiosulphate, \(\mathrm{Na}_2 \mathrm{~S}_2 \mathrm{O}_3\) gets oxidised by chlorine water.
\(
\mathrm{Na}_2 \mathrm{~S}_2 \mathrm{O}_3+4 \mathrm{Cl}_2+5 \mathrm{H}_2 \mathrm{O} \longrightarrow 2 \mathrm{NaHSO}_4\) \(+~8 \mathrm{HCl}
\)
\(\mathrm{Na}_2 \mathrm{~S}_2 \mathrm{O}_3\) gets oxidised by \(\mathrm{FeCl}_3\) into \(\mathrm{Na}_2 \mathrm{~S}_4 \mathrm{O}_6\)
\(
2 \mathrm{Na}_2 \mathrm{~S}_2 \mathrm{O}_3+2 \mathrm{FeCl}_3 \longrightarrow \mathrm{Na}_2 \mathrm{~S}_4 \mathrm{O}_6+2 \mathrm{FeCl}_2\) \(+~2 \mathrm{NaCl}
\)
Further, \(\mathrm{Na}_2 \mathrm{~S}_2 \mathrm{O}_3\) decomposes on treatment with dilute acids
\(
\mathrm{Na}_2 \mathrm{~S}_2 \mathrm{O}_3+2 \mathrm{HCl} \longrightarrow 2 \mathrm{NaCl}+\mathrm{SO}_2+\mathrm{S}~+\) \(\mathrm{H}_2 \mathrm{O}
\)
\(
\mathrm{Na}_2 \mathrm{~S}_2 \mathrm{O}_3+4 \mathrm{Cl}_2+5 \mathrm{H}_2 \mathrm{O} \longrightarrow 2 \mathrm{NaHSO}_4\) \(+~8 \mathrm{HCl}
\)
\(\mathrm{Na}_2 \mathrm{~S}_2 \mathrm{O}_3\) gets oxidised by \(\mathrm{FeCl}_3\) into \(\mathrm{Na}_2 \mathrm{~S}_4 \mathrm{O}_6\)
\(
2 \mathrm{Na}_2 \mathrm{~S}_2 \mathrm{O}_3+2 \mathrm{FeCl}_3 \longrightarrow \mathrm{Na}_2 \mathrm{~S}_4 \mathrm{O}_6+2 \mathrm{FeCl}_2\) \(+~2 \mathrm{NaCl}
\)
Further, \(\mathrm{Na}_2 \mathrm{~S}_2 \mathrm{O}_3\) decomposes on treatment with dilute acids
\(
\mathrm{Na}_2 \mathrm{~S}_2 \mathrm{O}_3+2 \mathrm{HCl} \longrightarrow 2 \mathrm{NaCl}+\mathrm{SO}_2+\mathrm{S}~+\) \(\mathrm{H}_2 \mathrm{O}
\)
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