An aqueous solution of X is added slowly to an aqueous solution of Y as shown in List I. The variation in conductivity of these reactions is given in List II. Match List I with List II and select the correct using answer the code given below the lists :

List - I	List - II
a. \(\underset{\quad\quad~~ X }{( C _2 H _5)_3 N}+\underset{ Y }{CH _3 COOH}\)	p. Conductivity decreases and then increases
b. \(\underset{\quad\quad~~ X }{KI (0.1 M )}+\underset{ Y }{AgNO _3(0.01 M )}\)	q. Conductivity decreases and then does not change much
c. \(\underset{\text X }{CH _3 COOH}+\underset{\text Y }{KOH}\)	r. Conductivity increases and then does not change much
d. \(\underset{\text X }{NaOH}+\underset{\text Y }{HI}\)	s. Conductivity does not change much and then increases

p) (C₂H₅)₃ N added to CH₃COOH
(C₂H₅)₃ NH⁺ and CH₃COO^- ions generated in solution, conductivity increases & then remains constant as (C₂H₅)₃ N is not dissociated when in excess.

q) KI_eq added to AgNO₃
$\left[{\text{Ag}}_{\text{(aq)}}^{+}+{\text{NO}}_{3\text{(aq)}}^{-}\right]+\text{KI}⟶\left[{\text{K}}_{\text{(aq)}}^{+}+{\text{NO}}_{3\text{(aq)}}^{-}\right]+\text{AgI}$
$\left({\text{Ag}}^{+}\&{\text{NO}}_3^{-}\right)$ ions replaced by $\left({\text{K}}_{\text{(aq)}}^{+}\&{\text{NO}}_{3\text{(aq)}}^{-}\right)$
conductivity does not change till complete precipitation but later on with additional KI_(aq) added conductivity will increase.

r) On addition of acetic acid to KOH. KOH fully dissociated replaced by
\(CH _3 COOH +\left( K ^{+}+ OH ^{-}\right) \longrightarrow[ CH _3 COO ^{-}\) \(+ K ^{+}]+ H _2 O\)
The net result is replacement of OH^- by CH₃COO^- ions whose ionic mobility is less so conductivity will decrease first and then will not change much due to addition of CH₃COOH(in excess) which will not be dissociated

s) On addition of NaOH to HI $\left({\text{H}}_{\text{(aq)}}^{+}+{\text{I}}_{\text{(aq)}}^{-}\right)+\text{NaOH}⟶\left({\text{Na}}^{+}+{\text{I}}^{-}\right)+{\text{H}}_2\text{O}$
there will be replacement of H⁺ by Na⁺ whose mobility is less than H⁺ which means conductivity will decrease first & then due to adding NaOH which is a strong electrolyte which fully dissociates, so conductivity will increase.