JEE Advanced · Chemistry · 18. Chemical Kinetics
A plot of the number of neutrons against the number of protons of the stable nuclei exhibits upwards deviation from linearity for atomic number, . For an unstable nucleus having ratio less than , the possible mode(s) of decay is (are):
- A decay ( emission)
- B Orbital of K-electron capture
- C Neutron emission
- D decay (positron emission)
Answer & Solution
Correct Answer
(D) decay (positron emission)
Step-by-step Solution
Detailed explanation
As ratio is less than , for possible decay mode, ratio should increase. The possible modes are -decay, K-capture and -decay. Hence, the correct options are and (In -decay or neutron decay, ratio will decrease further).
should increase. So,
[K-electron Capture]
[-decay]
should increase. So,
[K-electron Capture]
[-decay]
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Chemistry
- Paragraph:
The reaction of \(\mathrm{K}_{3}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\) with freshly prepared \(\mathrm{FeSO}_{4}\) solution produces a dark blue precipitate called Turnbull's blue. Reaction of \(\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\) with the \(\mathrm{FeSO}_{4}\) solution in complete absence of air produces a white precipitate \(\mathbf{X}\), which turns blue in air. Mixing the \(\mathrm{FeSO}_{4}\) solution with \(\mathrm{NaNO}_{3}\), followed by a slow addition of concentrated \(\mathrm{H}_{2} \mathrm{SO}_{4}\) through the side of the test tube produces a brown ring.
Question:
Precipitate \(\mathbf{X}\) isJEE Advanced 2021 Medium - The nitrogen containing compound produced in the reaction of withJEE Advanced 2016 Medium
- The complete hydrolysis of \(\mathrm{ICl}_2 \mathrm{ClF}_3\) and \(\mathrm{BrF}_5\), respectively, givesJEE Advanced 2025 Easy
- The option(s) with only amphoteric oxides is(are)JEE Advanced 2017 Easy
- Among cellulose, polyvinyl chloride, nylon and natural rubber, the polymer in which the intermolecular force of attraction is weakest inJEE Advanced 2009 Medium
- Which of the following liberates upon hydrolysis?JEE Advanced 2020 Medium
More PYQs from JEE Advanced
- Reaction of iso-propylbenzene with \(\mathrm{O}_2\) followed by the treatment with \(\mathrm{H}_3 \mathrm{O}^{+}\)forms phenol and a by-product \(\mathbf{P}\). Reaction of \(\mathbf{P}\) with 3 equivalents of \(\mathrm{Cl}_2\) gives compound \(\mathbf{Q}\). Treatment of \(\mathbf{Q}\) with \(\mathrm{Ca}(\mathrm{OH})_2\) produces compound \(\mathbf{R}\) and calcium salt \(\mathbf{S}\).
The correct statement(s) regarding \(\mathbf{P}, \mathbf{Q}, \mathbf{R}\) and \(\mathbf{S}\) is(are)JEE Advanced 2024 Hard - The reversible expansion of an ideal gas under adiabatic and isothermal conditions is shown in the figure. Which of the following statement(s) is (are) correct?
JEE Advanced 2012 Medium - The positive integer value of \(n>3\) satisfying the equation
\(\frac{1}{\sin \left(\frac{\pi}{n}\right)}=\frac{1}{\sin \left(\frac{2 \pi}{n}\right)}+\frac{1}{\sin \left(\frac{3 \pi}{n}\right)} \text { is }\)JEE Advanced 2011 Hard - The circuit shown in the figure contains an inductor \(L\), a capacitor \(C_0\), a resistor \(R_0\) and an ideal battery. The circuit also contains two keys \(\mathrm{K}_1\) and \(\mathrm{K}_2\). Initially, both the keys are open and there is no charge on the capacitor. At an instant, key \(K_1\) is closed and immediately after this the current in \(R_0\) is found to be \(I_1\). After a long time, the current attains a steady state value \(I_2\). Thereafter, \(\mathrm{K}_2\) is closed and simultaneously \(\mathrm{K}_1\) is opened and the voltage across \(C_0\) oscillates with amplitude \(V_0\) and angular frequency \(\omega_0\).

Match the quantities mentioned in List-I with their values in List-II and choose the correct option.
JEE Advanced 2024 Hard - A signal which can be green or red with probability \(\frac{4}{5}\) and \(\frac{1}{5}\) respectively, is received by station \(A\) and then transmitted to station B. The probability of each station receiving the signal correctly is \(\frac{3}{4}\). If the signal received at station \(B\) is green, then the probability that the original signal green isJEE Advanced 2010 Hard
- Let \((x, y)\) be any point on the parabola \(y^2=4 x\). Let \(P\) be the point that divides the line segment from \((0,0)\) to \((x, y)\) in the ratio \(1: 3\). Then, the locus of \(P\) isJEE Advanced 2011 Medium