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GUJCET · Physics · Electrostatic Potential and Capacitance
\(2 \mu F\) capacitor is connected with 50 V supply \& \(3 \mu F\) capacitor is connected with 100 V supply. Now after removing battery if two plates of same type of charges are placed to form new capacitor then potential difference is ________ V.
- A 75
- B 333
- C 200
- D 80
Answer & Solution
Correct Answer
(D) 80
Step-by-step Solution
Detailed explanation
(D)
common potential difference
\(V=\frac{Q_1+Q_2}{C_1+C_2}\)
\(\begin{array}{l}V=\frac{C_1 V_1+C_2 V_2}{C_1+C_2} \\ V=\frac{2 \times 10^{-6} \times 50+3 \times 10^{-6} \times 100}{2 \times 10^{-6}+3 \times 10^{-6}} \\ V=\frac{(100+300) \times 10^{-6}}{(2+3) \times 10^{-6}}=\frac{400}{5} \\ V=80 V\end{array}\)
common potential difference
\(V=\frac{Q_1+Q_2}{C_1+C_2}\)
\(\begin{array}{l}V=\frac{C_1 V_1+C_2 V_2}{C_1+C_2} \\ V=\frac{2 \times 10^{-6} \times 50+3 \times 10^{-6} \times 100}{2 \times 10^{-6}+3 \times 10^{-6}} \\ V=\frac{(100+300) \times 10^{-6}}{(2+3) \times 10^{-6}}=\frac{400}{5} \\ V=80 V\end{array}\)
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