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GUJCET · Physics · Alternating Current
A current of \(\frac{\mathbf{2 5}}{\pi} \mathbf{H z}\) frequency is passing through an AC circuit having series combination of \(R=100 \Omega\) and \(L=2 H\), the phase difference between voltage and current is ____________ .
- A \(90^{\circ}\)
- B \(60^{\circ}\)
- C \(30^{\circ}\)
- D \(45^{\circ}\)
Answer & Solution
Correct Answer
(D) \(45^{\circ}\)
Step-by-step Solution
Detailed explanation
(D) \(45^{\circ}\)
for RL circuit
\(
\begin{aligned}
\tan \phi & =\frac{\omega L}{R} \\
\tan \phi & =\frac{2 \pi \nu L}{R} \\
\therefore \tan \phi & =\frac{2 \pi \times \frac{25}{\pi} \times 2}{100} \\
\therefore \tan \phi & =1 \\
\therefore \quad \phi & =45^{\circ}
\end{aligned}
\)
for RL circuit
\(
\begin{aligned}
\tan \phi & =\frac{\omega L}{R} \\
\tan \phi & =\frac{2 \pi \nu L}{R} \\
\therefore \tan \phi & =\frac{2 \pi \times \frac{25}{\pi} \times 2}{100} \\
\therefore \tan \phi & =1 \\
\therefore \quad \phi & =45^{\circ}
\end{aligned}
\)
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