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GUJCET · Physics · Current Electricity
Two electric bulb of 40 W each are connected inseries. The power consumed by the combination will be _________.
- A 40 watt
- B 60 watt
- C 20 watt
- D 100 watt
Answer & Solution
Correct Answer
(C) 20 watt
Step-by-step Solution
Detailed explanation
(C)
Here \(P_1=40 watt , P_2=40 watt\)
for series connection
\(\begin{array}{l}P =\frac{P_1 P_2}{P_1+P_2} \\ P =\frac{40 \times 40}{40+40} \\ \therefore P=20 \text { watt }\end{array}\)
Here \(P_1=40 watt , P_2=40 watt\)
for series connection
\(\begin{array}{l}P =\frac{P_1 P_2}{P_1+P_2} \\ P =\frac{40 \times 40}{40+40} \\ \therefore P=20 \text { watt }\end{array}\)
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