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GUJCET · Physics · Electrostatic Potential and Capacitance
Work done in placing a charge of \(8 \times 10^{-18} C\) on a capacitor of capacitance \(800 \mu F\) is _________.
- A \(4 \times 10^{-32} J\)
- B \(32 \times 10^{-32} J\)
- C \(3.1 \times 10^{-26} J\)
- D \(16 \times 10^{-32} J\)
Answer & Solution
Correct Answer
(A) \(4 \times 10^{-32} J\)
Step-by-step Solution
Detailed explanation
(A)
work done \(W = U =\frac{ Q ^2}{2 C }\)
\(\begin{array}{l}W=\frac{\left(8 \times 10^{-18}\right)^2}{2 \times 800 \times 10^{-6}} \\ W=4 \times 10^{-32} J\end{array}\)
work done \(W = U =\frac{ Q ^2}{2 C }\)
\(\begin{array}{l}W=\frac{\left(8 \times 10^{-18}\right)^2}{2 \times 800 \times 10^{-6}} \\ W=4 \times 10^{-32} J\end{array}\)
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