Two bulbs of 250 V and 100 W are first connected in series and then in parallel with a supply of 250 V . Total power in each of the cases will be __________ respectively.

A 50 W, 100 W
B 50 W, 200 W
C 100 W, 50 W
D 200 W, 150 W

Verified Solution

Answer & Solution

Correct Answer

(B) 50 W, 200 W

Step-by-step Solution

Detailed explanation

(B)
for series connection
\(\begin{array}{l}P_s=\frac{P_1 P_2}{P_1+P_2} \\P_s=\frac{100 \times 100}{100+100} \\P_s=50 W\end{array}\)
for parallel connection
\(\begin{array}{l}P_P=P_1+P_2 \\P_P=100+100 \\P_P=200 W\end{array}\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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