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GUJCET · Physics · Current Electricity
The carbon resistor has three orange bands The maximum value of resistance offered by the resistor will be _________.
- A \(49.6 k \Omega\)
- B \(39.6 k \Omega\)
- C \(33 k \Omega\)
- D \(26.4 k \Omega\)
Answer & Solution
Correct Answer
(B) \(39.6 k \Omega\)
Step-by-step Solution
Detailed explanation
(B)
As per colour code orange \(\rightarrow 3\)
Value of resistor
\(\begin{array}{l}=\left(33 \times 10^3 \pm 20 \%\right) \Omega \\ =(33 k \Omega \pm 20 \%)\end{array}\)
The maximum value of resistance
\(\begin{array}{l}=33000+20 \% \text { of } 33000 \\ =33000+6600 \\ =39600 \Omega \\ =39.6 k \Omega\end{array}\)
As per colour code orange \(\rightarrow 3\)
Value of resistor
\(\begin{array}{l}=\left(33 \times 10^3 \pm 20 \%\right) \Omega \\ =(33 k \Omega \pm 20 \%)\end{array}\)
The maximum value of resistance
\(\begin{array}{l}=33000+20 \% \text { of } 33000 \\ =33000+6600 \\ =39600 \Omega \\ =39.6 k \Omega\end{array}\)
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