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GUJCET · Physics · Electromagnetic Induction
The coil having 1000 turns \& Area of \(0.10 m^2\) rotates at half a revolution per second and it is placed in a uniform magnetic field of 0.01 T . perpendicular to the axis of rotation of coil. Then maximum emf voltage generated in coil is ________ V.
- A 0.314
- B 5.0
- C 3.14
- D 0.5
Answer & Solution
Correct Answer
(C) 3.14
Step-by-step Solution
Detailed explanation
C
\(\begin{array}{l}v=0.5 Hz \\ \omega=2 \pi v \\ \omega=2 \pi(0.5) \\ \omega=\pi \cdot \frac{ rad }{ s }\end{array}\)
\(\operatorname{maximum} \varepsilon=\) NAB \(\omega\)
\(\begin{array}{l}\varepsilon_{\max }=1000 \times 0.10 \times 0.01 \times \pi \\ \varepsilon_{\max }=\pi \\ \varepsilon_{\max }=3.14 V\end{array}\)
\(\begin{array}{l}v=0.5 Hz \\ \omega=2 \pi v \\ \omega=2 \pi(0.5) \\ \omega=\pi \cdot \frac{ rad }{ s }\end{array}\)
\(\operatorname{maximum} \varepsilon=\) NAB \(\omega\)
\(\begin{array}{l}\varepsilon_{\max }=1000 \times 0.10 \times 0.01 \times \pi \\ \varepsilon_{\max }=\pi \\ \varepsilon_{\max }=3.14 V\end{array}\)
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