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GUJCET · Physics · Moving Charges and Magnetism
A solenoid of length 0.5 m has a radius of 1 cm and is made up of 1000 turns. It carries a current of 10 A . What is the magnitude of the magnetic field inside the solenoid ?
- A \(2.51 \times 10^{-2} T\)
- B \(1.71 \times 10^{-2} T\)
- C \(6.28 \times 10^{-3} T\)
- D \(7.23 \times 10^{-3} T\)
Answer & Solution
Correct Answer
(A) \(2.51 \times 10^{-2} T\)
Step-by-step Solution
Detailed explanation
A
\(\begin{array}{l} B =\mu_0 n I =\mu_0 \frac{N}{l} I \\ B =4 \pi \times 10^{-7} \times \frac{1000}{0.5} \times 10 \\ B=2.51 \times 10^{-2} T\end{array}\)
\(\begin{array}{l} B =\mu_0 n I =\mu_0 \frac{N}{l} I \\ B =4 \pi \times 10^{-7} \times \frac{1000}{0.5} \times 10 \\ B=2.51 \times 10^{-2} T\end{array}\)
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