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GUJCET · Physics · Alternating Current
For a series LCR circuit with \(L=2 H, C=18 \mu F\) and \(R=10 \Omega\). What is the value of \(Q\) factor of this circuit ?
- A 55.55
- B 44.44
- C 22.22
- D 33.33
Answer & Solution
Correct Answer
(D) 33.33
Step-by-step Solution
Detailed explanation
(D) 33.33
\(Q=\frac{1}{R} \sqrt{\frac{L}{C}}\)
\(Q=\frac{1}{10} \sqrt{\frac{2}{18 \times 10^{-6}}}\)
\(Q=\frac{1 \times 10^{3}}{10 \times 3}=\frac{100}{3}\)
\(Q=33.33\)
\(Q=\frac{1}{R} \sqrt{\frac{L}{C}}\)
\(Q=\frac{1}{10} \sqrt{\frac{2}{18 \times 10^{-6}}}\)
\(Q=\frac{1 \times 10^{3}}{10 \times 3}=\frac{100}{3}\)
\(Q=33.33\)
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