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GUJCET · Physics · Atoms
The radius of the innermost electron orbit of a hydrogen atom is \(5.3 \times 10^{-11} \mathrm{~m}\). What is the radius of the n = 3 orbit?
- A \(1.59 \times 10^{-10} \mathrm{~m}\)
- B \(1.06 \times 10^{-10} \mathrm{~m}\)
- C \(1.43 \times 10^{-9} \mathrm{~m}\)
- D \(4.77 \times 10^{-10} \mathrm{~m}\)
Answer & Solution
Correct Answer
(D) \(4.77 \times 10^{-10} \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
\(r_n = r_1 n^2\) \(r_3 = (5.3 \times 10^{-11} \mathrm{~m}) (3)^2\)
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