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GUJCET · Physics · Ray Optics and Optical Instruments
Time taken by the sunlight to pass through a slab of \(\mathbf{4 ~ c m}\) and refractive index \(\mathbf{1 . 5}\) is ________ sec.
- A \(2 \times 10^{11}\)
- B \(2 \times 10^{-10}\)
- C \(2 \times 10^{11}\)
- D \(2 \times 10^{-8}\)
Answer & Solution
Correct Answer
(B) \(2 \times 10^{-10}\)
Step-by-step Solution
Detailed explanation
(B) \(2 \times 10^{-10}\)
>\(
\begin{aligned}
n=\frac{c}{v} & =\frac{c d}{t} \quad\left(\because v=\frac{d}{t}\right) \\
\therefore t & =\frac{n d}{c} \\
\therefore t & =\frac{1.5 \times 4 \times 10^{-2}}{3 \times 10^{8}} \\
\therefore t & =2 \times 10^{-10} \mathrm{~s}
\end{aligned}
\)
>\(
\begin{aligned}
n=\frac{c}{v} & =\frac{c d}{t} \quad\left(\because v=\frac{d}{t}\right) \\
\therefore t & =\frac{n d}{c} \\
\therefore t & =\frac{1.5 \times 4 \times 10^{-2}}{3 \times 10^{8}} \\
\therefore t & =2 \times 10^{-10} \mathrm{~s}
\end{aligned}
\)
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