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GUJCET · Physics · Electric Charges and Fields
The force between two point charges placed in a material medium of dielectric constant \(K\) is \(F\). If the material is removed, then the force between them becomes _________.
- A \(F \sqrt{ K }\)
- B FK
- C \(\frac{F}{\sqrt{K}}\)
- D \(\frac{ F }{ K }\)
Answer & Solution
Correct Answer
(B) FK
Step-by-step Solution
Detailed explanation
(B)
\(\begin{array}{l} F _{\text {medium }}=\frac{ F _{\text {air }}}{ K } \\ \text { But } F _{\text {medium }}= F \\ \therefore F =\frac{ F _{\text {air }}}{ K } \therefore F _{\text {air }}= FK \end{array}\)
\(\begin{array}{l} F _{\text {medium }}=\frac{ F _{\text {air }}}{ K } \\ \text { But } F _{\text {medium }}= F \\ \therefore F =\frac{ F _{\text {air }}}{ K } \therefore F _{\text {air }}= FK \end{array}\)
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