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GUJCET · Physics · Electromagnetic Induction
The instantaneous magnetic flux associated with a closed loop of resistance \(10 \Omega\) is given by \(\phi=2 t^2-5 t+1\), then the magnitude of induced current at \(t =0.25 s\) will be _________ .
- A 0.4 A
- B 1 A
- C 4.0 A
- D 0.04 A
Answer & Solution
Correct Answer
(A) 0.4 A
Step-by-step Solution
Detailed explanation
A
Induced emf \(\varepsilon=-\frac{d \phi}{d t}\)
\(\begin{array}{l}\varepsilon=-\frac{d}{d t}\left(2 t^2-5 t+1\right) \\ \varepsilon=-(4 t-5) \\ \varepsilon=-(4 \times 0.25-5) \\ \varepsilon=4 V\end{array}\)
Induced emf \(\varepsilon=-\frac{d \phi}{d t}\)
\(\begin{array}{l}\varepsilon=-\frac{d}{d t}\left(2 t^2-5 t+1\right) \\ \varepsilon=-(4 t-5) \\ \varepsilon=-(4 \times 0.25-5) \\ \varepsilon=4 V\end{array}\)
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