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GUJCET · Physics · Electrostatic Potential and Capacitance
Charges \(1 \mu C\) are placed at each of the four corners of a square of side \(2 \sqrt{2} m\). The potential at the point of intersection of the diagonals is _________.
- A \(18 \times 10^3 V\)
- B 1800 V
- C \(18 \sqrt{2} \times 10^3 V\)
- D None of these.
Answer & Solution
Correct Answer
(A) \(18 \times 10^3 V\)
Step-by-step Solution
Detailed explanation
(A)

digonal length\(=\sqrt{(2 \sqrt{2})^2+(2 \sqrt{2})^2}=4 m\)
distance of each vertex from the\(\text { center }=\frac{4}{2}=2 m\)
potential at center
\(\begin{aligned} & V =\frac{4 k q}{r} \\ \therefore & V=\frac{4 \times 9 \times 10^9 \times 1 \times 10^{-6}}{2} \\ \therefore & V=18 \times 10^3 V\end{aligned}\)

digonal length\(=\sqrt{(2 \sqrt{2})^2+(2 \sqrt{2})^2}=4 m\)
distance of each vertex from the\(\text { center }=\frac{4}{2}=2 m\)
potential at center
\(\begin{aligned} & V =\frac{4 k q}{r} \\ \therefore & V=\frac{4 \times 9 \times 10^9 \times 1 \times 10^{-6}}{2} \\ \therefore & V=18 \times 10^3 V\end{aligned}\)
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