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GUJCET · Physics · Electrostatic Potential and Capacitance
The electric potential at the surface of an atomic nucleus (Z=50) of radius \(9 \times 10^{-15} m\) is __________.
- A 9 volt
- B \(9 \times 10^5\) volt
- C 80 volt
- D \(8 \times 10^6\) volt
Answer & Solution
Correct Answer
(D) \(8 \times 10^6\) volt
Step-by-step Solution
Detailed explanation
(D)
\(\begin{aligned} V & =\frac{k q}{r} \\ \therefore \quad V & =\frac{k Ze }{r} \\ \therefore \quad V & =\frac{9 \times 10^9 \times 50 \times 1.6 \times 10^{-19}}{9 \times 10^{-15}} \\ \therefore \quad V & =8 \times 10^6 volt \end{aligned}\)
\(\begin{aligned} V & =\frac{k q}{r} \\ \therefore \quad V & =\frac{k Ze }{r} \\ \therefore \quad V & =\frac{9 \times 10^9 \times 50 \times 1.6 \times 10^{-19}}{9 \times 10^{-15}} \\ \therefore \quad V & =8 \times 10^6 volt \end{aligned}\)
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